The equation of the line in the graph is - JAMB Mathematics 2020 Question

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Gradient of line = \(\frac{\text{Change in y}}{\text{Change in x}}\) = \(\frac{y_2 - Y}{x_2 - x}\) 

y\(_2\)  = 0\(_1\) 

Y\(_1\)  = 4 

x\(_2\)  = 3 and x\(_1\)  = 0

\(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\)

The general equation of a straight line is y = m x + c , where is the gradient and the coordinates of the y-intercept.

At x = 0, y = c. y-intercept = 4 

y = 4x + \(\frac{4}{3}\) multiply through y 

3y = 4x + 23